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By admin on December 11, 2011
How much work does an elevator motor do to lift a 1000 kg elevator a height of 100 m? How much power must the motor supply to do this in 50 s at constant speed?
Posted in Uncategorized | Tagged elevator, elevator motor, height, kg, work |
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Work = Force x Distance
So in this case you will need to turn the 1000kg into a force. To do that you just multiply the Weight by Gravity. So 1000 x 9.81 = 9810N
Therefore, w = f x d, so w = 9810 x 100 = 981000 Joules.
Been looking at my notes and Power = work / time.
So: p = 981000/50 = 19620 watts.
Work = F*d
F = 1000kg * g
d = 100m
Work = 9.81 x 10^5 J
Power = Work/t
= 9.81 x 10^5 J / 50 s
= 1.962 x 10^4 W